1) (40 pts. total) Using the Hf-V phase diagram on page 6, if you start with 100 kg of a Hf-V mixture at
2000oC and 30 wt. % V and cool down very slowly to points A (2000oC), B (1495oC,
just above the line), C (1190oC, just above the line), and D (1000oC), sketch the microstructure
associated with each letter, determine what phases are present at each letter, determine the
compositions for each phase, and determine the weight in each phase.
Point A) Microstructural drawing Phase(s) present
Weight % of Vanadium in each phase
Weight of each phase
Point B) Microstructural drawing Phase(s) present
Weight % of Vanadium in each phase
Weight of each phase
Point C) Microstructural drawing Phase(s) present
Weight % of Vanadium in each phase
Weight of each phase
Point D) Microstructural drawing Phase(s) present
Weight % of Vanadium in each phase
Weight of each phase
2) Molybdenum carbides are efficient catalysts for taking the nitrogen out of molecules in crude oil as ammonia. Prior to use as a catalyst, the molybdenum carbide should be reduced using hydrogen.
that the Mo carbon has a crystal diameter of 3 nm and is an active catalyst at 600 K,
and that the activation energy for diffusion is 38000 J/mole. First, estimate the
diffusivity of carbon in m2/sec.
D = 1.4 x 10-8 * exp (-Ediff/(8.314*T)), where D for carbon is in m2/sec and T is in K.
Then, using the dimensionless group relationship you learned with regard to diffusion, estimate
the amount of time that it would take the carbon to diffuse the length of the diameter of
the crystal, assuming that if the dimensionless group is approximately one, then the
carbon atom had sufficient time to diffuse across the entire diameter of the crystal.
label the following: ultimate compressive strength (UCS), yield stress (YS), modulus of
elasticity (E), and rupture stress (RS). Points will be assigned for getting trends correct.
than, less than, or equal signs to indicate whether a material cooled from the liquid
state will have superior properties if cooled quickly or cooled very slowly.
Ductility Cooled quickly Cooled very slowly
Corrosion resistance Cooled quickly Cooled very slowly
Ultimate compressive strength Cooled quickly Cooled very slowly
Melting point Cooled quickly Cooled very slowly
3) (26 pts.) Given the time-temperature transformation diagram on page 6, what would be the phases
present for a 4340 steel with no alloying elements? Use the bottom of this page
to show any work, including any phase diagram-related calculations (worth 5 pts.).
Presume that the M(90%) line is actually M(100%).
quenched to room temperature
quenched to 350oC, held at 350oC for 60 seconds, and finally quenched to room temperature
held there for 1000 seconds, and finally quenched to room temperature
quenched to room temperature
quenched to room temperature
Necessary Steel Phase Diagram Calculations (continued on p. 6 if necessary):
Total Page 1 ____/30
Total Page 2 ____/25
Total Page 3 ____/19
Total Page 4 ____/26
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